x^-2=-40/5

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Solution for x^-2=-40/5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x^-2 = -40/5 // + -40/5

x^-2-(-40/5) = 0

x^-2+8 = 0

1*x^-2 = -8 // : 1

x^-2 = -8

-2 < 0

1/(x^2) = -8 // * x^2

1 = -8*x^2 // : -8

-1/8 = x^2

x belongs to the empty set

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